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Beakjoon&프로그래머스/Java

[LeetCode/Java] How Many Numbers Are Smaller Than the Current Number

by 현장 2025. 11. 24.

-Code

class Solution {
    public int[] smallerNumbersThanCurrent(int[] nums) {
        int numLen = nums.length;
        int[] answer = new int[numLen];

        for (int i = 0; i < numLen; i++) {
            for (int j = 0; j < numLen; j++) {
                if (nums[i] > nums[j]) answer[i]++;
            }
        }

        return answer;
    }
}